Hi, this is my M-file named nle.m
function F = nle(x,b1,b2)
F = [(1-x(1))*x(2)*30+(1-x(1))*(1-x(2))*150-b1;
x(1)*189+(1-x(1))*x(2)*55.5+(1-x(1))*(1-x(2))*70-b2];
b1 and b2 are vectors (e.g. 5x1)
b1 = [24.1230 24.8000 25.4770 26.1540 26.8310]'
b2 = [67.4820 67.7000 67.9170 68.1340 68.3510]'
and the start point
I would find the zero for each pair of b1 and b2, then I expect five pair of solutions. I write
for i=1:length(b1)
fun = @(x) nle(x, b1(i), b2(i));
x = fsolve(fun, x0);
end
Appears five time the statement: Optimization terminated: first-order optimality is less than options.TolFun
but in the workspace only the last solution is stored
If I write
for i=1:length(b1)
fun = @(x) nle(x, b1(i), b2(i));
x(i) = fsolve(fun, x0);
end
Optimization terminated: first-order optimality is less than options.TolFun.
??? In an assignment A(I) = B, the number of elements in B and I must be the same.
where is the mistake?
