weighted average w/ matlab

166 次查看(过去 30 天)
Hi guys, I have calculated different errors over a range.
let's say a range with a linear space from 100 to 150.
For this range I calculate a variable Y so Y(range).
Now I want to calculate the mean of the variable, but I want to give the values close to 125 more weight than the values close to 100 and 150, with the heaviest weight being 125.
I can't seem to figure it out, can someone help me out?

采纳的回答

Udit Gupta
Udit Gupta 2015-9-2
You can do something like -
weight=normpdf(range,centerPoint,spread);
wAvg = sum(Y(range).*weight)/sum(weight);
In you example centerPoint will be 125, and larger the spread more slowly the weight will decrease away from centerPoint.
  3 个评论
Udit Gupta
Udit Gupta 2015-9-2
spread is not a function. It can be any value. Bigger the value bigger the spread is. For example spread = 100 will provide a wide and gentle slope and spread = 50 will produce a steeper slope.
Regi streer
Regi streer 2015-9-3
编辑:Regi streer 2015-9-3
ah okay, it's a normal distribution i missed that. Thanks!

请先登录,再进行评论。

更多回答(1 个)

dpb
dpb 2015-9-2
Have to decide how much you want the weights to be, but the general idea would be sotoo--
>> y=randi([100 150],40,1); % some random data
>> mean(y) % mean should be near 125
ans =
123.9750
>> w=(y/100).^2;w=w/mean(w); % compute a weight dependent on y; normalize to 1 overall...
>> [min(w) max(w)] % what's look like???
ans =
0.6400 1.4399
>> mean(y.*w) % how much did we change it???
ans =
128.0471
>>
  2 个评论
Regi streer
Regi streer 2015-9-2
But this does not give me exactly more weight at 125 in my problem right?
dpb
dpb 2015-9-2
编辑:dpb 2015-9-3
My bad; somehow I read too quickly that the max weight was to be 150, not midpoint. Use a functional with a max at 125; could be the normal pdf as another poster showed or whatever you wish but the same idea works.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Descriptive Statistics 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by