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how to write Binary table in simple way ?

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Henry Buck
Henry Buck 2015-9-12
评论： Walter Roberson 2019-7-28
Hi there,
1. How to create Binary code (like this one below) in a simple way?
0 0 0 0
0 0 0 1
0 0 1 0
0 0 1 1
0 1 0 0
0 1 0 1
0 1 1 0
0 1 1 1
1 0 0 0
1 0 0 1
1 0 1 0
1 0 1 1
1 1 0 0
1 1 0 1
1 1 1 0
1 1 1 1
2. how to print only the relevant rows like:
0 0 1 1
0 1 0 1
0 1 1 0
1 0 0 1
1 0 1 0
1 1 0 0
only the rows that has 2 bits that equal to 1.....
Thanks,
Henry

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采纳的回答

Walter Roberson
Walter Roberson 2015-9-12
What happens if you use dec2bin(13) - '0' ?
A way to calculate how many values are set in a row is to sum() the row.
You should also investigate logical indexing
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Walid KESSAL
Walid KESSAL 2018-3-16
Here's how you can take care of that problem Mr.Henry Buck.
n=4; tab=[];
for i=0:(2^n-1)
table(i+1,:) = dec2bin(i,n);
tab = [tab;table(i+1,:)];
end
table = tab
the result is this
Walter Roberson
Walter Roberson 2019-7-28
That code is redundant: just assigning into table() is enough without needing to build that tab variable.

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Pierre Bulens
Pierre Bulens 2019-7-28
dec2bin function gives the table :
binarytable.PNG
to get the rows containing 2 bits equal to 1, use the sum function and logical indexing
rows with 2 ones.PNG
the sum function gives the number of 1s in each row,
the '== 2' part selects the wanted rows

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