Legend entries all same color in Matlab 2015b

2015 9 14
5 个回答
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更新时间：2017 2 16
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3 个投票

I just updated to Matlab 2015b, and the frustration has already begun.
I am making a simple scatter plot with multiple data sets. Each data set has a different color, but the legend shows points all in the same color. Example code showing problem below: (ONLY IN 2015b)
---------------
x = 1:1:100;
y1 = rand(1,100);
y2 = rand(1,100);
y3 = rand(1,100);
figure;
scatter(x,y1);
hold on;
scatter(x,y2,'*');
scatter(x,y3);
legend('random 1','random 2','random 3') ;
---------------
The different symbol choice on 'random 2' illustrates that the problem is only with color, and not with referencing the same handle for each.
Help much appreciated!
Maddie

4 个评论
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Star Strider
Star Strider 2015-9-14
Definitely a bug. Nothing I tried (specifying colours and markers, returning handles and sending them to legend as arguments) alters what you saw. Since you discovered it, report it as a bug to TMW Tech Support.
the cyclist
the cyclist 2015-9-14
Agree on bug report suggestion. This code works properly for me in 2015a, and not 2015b.
Talfan Evans
Talfan Evans 2016-7-4
Also found this bug. Easy to use the plot command but specify the marker type, i.e:
scatter(x,y,'r')
produces the same output as:
plot(x,y,'or')
The bug doesn't seem to affect the plot command.
joebob
joebob 2017-2-16
Hello, found a way to show the color in the legend by forcing the `MarkerFaceColor` property:
h = scatter(x_data, y_data, area_data, 'green', 'filled', 'MarkerFaceColor', 'green');

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Mike Garrity
Mike Garrity 2015-9-15

2 个投票

That sounds like bug 1283854. There's a patch and some workarounds at that link.

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Madison Smith
Madison Smith 2015-9-15
That is exactly it. Thanks so much!
lis coffey
lis coffey 2016-7-4
i guess the problem is only with color, and not with referencing the same handle for each. Thanks \ Qwikfix \

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更多回答（4 个）

Jacob Kamminga
Jacob Kamminga 2016-6-28

3 个投票

From the bugreport, Use this workaround when the points within each scatter plot are different colors:
Call the legend function with two or more output arguments:
s1 = scatter(1:10,1:10,[],1:10);
hold on
s2 = scatter(2:11,1:10,[],26:35);
[h, ~] = legend('show');
Tony L.
Tony L. 2015-9-15

0 个投票

There must be a cleaner way to do this than the below, but gscatter seems to do the right thing:
x = 1:1:100;
y1 = rand(1,100);
y2 = rand(1,100);
y3 = rand(1,100);
g1 = repmat(1,length(y1),1);
g2 = repmat(2,length(y2),1);
g3 = repmat(3,length(y3),1);
ds = [x', y1', g1; x', y2', g2; x', y3', g3];
figure;
gscatter(ds(:,1), ds(:,2), ds(:,3));
legend('random 1','random 2','random 3') ;
SHR
SHR 2016-3-1

0 个投票

I have a similar issue. My data set is a table with multiple variables over time associated with specific locations. I wanted to graph all variables (y axis) over time on one scatter plot only for one location. Thus I converted the dates to DateNumebers and restricted the variables by location e.g., Y1-Znppm(SiteCat=='location_x'. The legend has the same symbol color. Is there an easier way to circumvent the bug?

0 个投票

and the bloody doesn't work. MATLAB is horrible

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