How to bin for scatter plot from two data series?
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Sir i have two data series say
a b
25.36737061 -27.47956892
20.54391479 -23.68162398
16.76391602 -16.65254461
9.47177124 -19.20600915
16.25158691 -18.56570783
4.462646484 -14.39363913
7.785919189 -14.98048449
12.27481079 -18.49125231
4.851806641 -19.91135093
2.111236572 -5.049334665
-1.457702637 -6.51219601
1.85055542 -1.299793246
and i want to plot for a=0-5,6-10,11-15,16-20 with the corresponding average and standard deviation of b. Please help me with a easy way since the series are very large?
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Star Strider
2015-9-15
编辑:Walter Roberson
2015-9-15
This seems to work:
m = [25.36737061 -27.47956892
20.54391479 -23.68162398
16.76391602 -16.65254461
9.47177124 -19.20600915
16.25158691 -18.56570783
4.462646484 -14.39363913
7.785919189 -14.98048449
12.27481079 -18.49125231
4.851806641 -19.91135093
2.111236572 -5.049334665
-1.457702637 -6.51219601
1.85055542 -1.299793246];
binedge = 0:5:20; % Define Bin Edges
[acount, idx] = histc(m(:,1), binedge); % Bin ‘a’, Return Index Vector
meanb = accumarray(idx+1, m(idx+1,2), [], @mean); % Get Mean Of Corresponding ‘b’
figure(1)
bar(binedge, acount, 'histc')
grid
One of the bin edge values is zero, and that doesn’t work as an index for accumarray, so I added 1 to the index values. That doesn’t affect the calculation.
4 个评论
Star Strider
2015-9-16
I didn’t specifically test the code for the standard deviation, but it should work as you wrote it, providing there are no NaN values in your data.
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