To put value in the specific column of uitable
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A uitable is constructed like this:
a=[1 2 3 0;1 2 4 5;0 9 7 0;1 3 4 6]; a=num2cell(a)
First the matrix is like this:
1 2 3 0
1 2 4 5
0 9 7 0
1 3 4 6
Therefore I need to construct the code based on the algorithm below:
1.In first row, I need to check either the value in end column is zero or not. If the value is zero,I need to shift the end column into previous column. If the element is zero again,the operation will proceed again, else the end column will fix.
2. In the end column, the value 55 will replace the current value.
3. This process will proceed to next row.
Finally,the matrix will become like this:
1 2 55 0
1 2 4 55
0 9 55 0
1 3 4 55
I need help to solve this problem. Thank you very much for your concern.
4 个评论
Walter Roberson
2011-12-20
So the rule is just "Change the last non-zero entry in the column to the value 55" ?
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Andrei Bobrov
2011-12-20
s = size(a);
j1 = arrayfun(@(x)find(a(x,:),1,'last'),1:s(1));
a(sub2ind(s,1:s(1),j1)) = 55;
OR if a - cell array
a1 = cellfun(@(x)x>0,a);
a(fliplr(cumsum(a1(:,end:-1:1),2))==1 & a1) = {55};
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