To calculate value in a uitable

2 次查看(过去 30 天)
In a uitable table, I have produce a matrix as below:
>> a= [1 1 1 2 2 3 3 3 4 ; 3 3 1 4 4 4 3 1 1; 3 3 2 4 1 1 1 3 2]
a =
1 1 1 2 2 3 3 3 4
3 3 1 4 4 4 3 1 1
3 3 2 4 1 1 1 3 2
Therefore,in each row, I need to calculate the marks occur based on conditions below:
1. if no 3 occur in three cells continuously therefore the mark charged is 30.
2. if no 3 occur in two cells continuously and then followed by no 1 in the next cell, the mark charged is -20.
3. if no 3 occur in a cell and then followed by no 1 in the next cell, the mark charged is -10.
4. if no 3 occur in two cells continuously and then followed by no 2 in the next cell, the mark charged is -20.
5. if no 3 occur in a cell and then followed by no 2 in the next cell, the mark charged is 0.
Then, in each row, the total marks will calculate. Finally the result will be save in a matrix like this:
marks =
-30
-30
-20
This marks also will total to become an X value as below:
X = -80
How can I code this problem in matlab? Please help me and thank you.

采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-12-21
try this code, I cant check now
s = size(a);
b = zeros(s);
b(abs(a - 3) < 1e3*eps) = -10;
k = [true(s(1),1) diff(a,1,2)~=0].*a;
p = arrayfun(@(x)10*nnz(strfind(k(x,:),[3 2])),(1:s(1))');
marks = sum(b,2) + p;

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Develop Apps Using App Designer 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by