Order of magnitude (10 times greater) execution time resulting from order of computations in a script file that are otherwise identical.
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I have two script files attached that are computationally identical except for the positioning of one equation in a nested set of for-loops. "DynamWave_Ponding_2D_V_Chan_Mod1.m" has the single equation at line 91 (commented as "fast position"). "DynamWave_Ponding_2D_V_Chan_Mod2.m" has the same equation moved to line 165 (commented as "slow position"). There is no difference logically or computationally in either position (that I can determine), but the ..Mod1.m executes 10 times faster than the ..Mod2.m . I would like to learn why it makes such a major difference in the execution times. Thanks.
5 个评论
the cyclist
2015-9-24
They take equal time on my Mac using R015b.
Robert Eli
2015-9-24
the cyclist
2015-9-24
I ran the code in 2015a, and both versions your code again run in comparable time. Interestingly, it was twice as fast in 2015a. :-(
Robert Eli
2015-9-25
采纳的回答
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Philip Borghesani
2015-9-25
2 个投票
This appears to be a bug/limitation in the 64 bit JIT in MATLAB versions prior to R2015b. Other versions of MATLAB don't show the performance difference between the two line locations.
It does look like R2015b lost some performance when running this code. Look to future versions to recover the performance back to your best case example.
Looking at this code my first thought is that some reorganization and vectorization might help improve the performance and make it more understandable, allowing further optimizations and people not familiar with it to offer useful suggestions on performance and vectorization improvements.
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