Function Output Not Displaying

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Krish Desai
Krish Desai 2015-9-27
回答： Walter Roberson 2015-9-27
function output = IsMagic(n)
A= zeros(n);
r=n;
c=n;
row_index = 1;
while row_index <= r
col_index=1;
while col_index <= c
A(row_index,col_index) = randi(1*n.^2);
col_index=col_index + 1;
end
row_index= row_index +1;
end
matrix=A;
columnsum=sum(matrix);
disp ('The sum for the columns is:')
fprintf ('%d,\n', columnsum)
rowsum=sum(matrix,2);
disp ('The sum for the rows isL')
fprintf ('%d,\n', rowsum)
d1=sum(diag(matrix));
d2=sum (diag(flip(A)));
disp ('The sum for the diagonals is')
fprintf ('%d, %d \n',d1,d2)
if numel(unique(columnsum))==1
if numel(unique(rowsum))==1
if numel(unique(d1))==1
if numel (unique(d2))==1
if (columnsum(1)==(rowsum(1))&& (columnsum(1))== (d1(1)) && (columnsum(1))==(d2(1)))
output=1;
else
output=0;
end
end
end
end
end
end
The purpose of this code is to create a function called isMagic. The function takes one input n, creates a square matrix of size n × n using random integers between 1 and n2,and returns the logical value true (1) if the resulting matrix is a magic square and false(0) if it not a magic square.
I have done everything, but for some reason the output is not displaying. What am I doing wrong?

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采纳的回答

Walter Roberson
Walter Roberson 2015-9-27
You do not assign output in some cases. You have a series of
if this
if that
if theother
output=1
else
output=0;
end
end
end
Consider what would happen if "this" is not true: it would never get to try "that" and "the other" to assign to output.
One way of handling this is to assign 0 to output before the "if" structure and then only assign 1 in the case you can prove that it is "perfect". In all the other cases output would stay 0 which is what you want.
But you should also look at the "&" and "&&" operators
if this & that & theother

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