hi, if i have array=[89 130 150 180...],in 1st iteration i need to perform "1:array(1)",in 2nd iteration i need "array(1)+1 :array(2)",in 3rd iteration i need "array(2)+1 :array(3)" and so on,i tried a lot,plz help me

1 次查看（过去 30 天）
kaavya subramani
kaavya subramani 2015-9-30
评论： Walter Roberson 2015-10-2
help plz

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2015-9-30
编辑：Walter Roberson 2015-10-2
array=[89 130 150 180...]
tarray = [1 array];
for K = 1 : length(tarray)-1
tarray(K):tarray(K+1)
end

更多回答（1 个）

Julia
Julia 2015-9-30
Hi,
my suggestion is:
do the first iteration outside the loop, the remaining can be done within:
1:array(1);
% do s.th.
for i=1:size(array)-1
(array(i)+1) : array(i+1);
% do s.th.
end

类别

在 Help Center 和 File Exchange 中查找有关 Images 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by