Undefined operator / for input arguements of type cell.

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Anas Abou Allaban
Anas Abou Allaban 2015-10-11
编辑： dpb 2015-10-11
I realize this question may have been asked a billion times, but I can't for the life of me see why its popping up with my code. I'm calculating the maximum value in a data set 'bridge1Load' through this loop:
maxLoad1 = 0;
for n = 1:length(bridge1Load)
for k = 1
if bridge1Load(n, k) > maxLoad1
maxLoad1 = bridge1Load(n, k);
end
end
end
and my bridge weight is a user input from:
bridge1WeightInput = inputdlg('Please enter the weight of bridge #1','Bridge #1 Weight');
I'm trying to calculate the strength to weight ratio via:
s2wRatio1 = maxLoad1 / bridge1Weight;
but I keep getting the error stated above.
  2 个评论
Anas Abou Allaban
Anas Abou Allaban 2015-10-11
Note that I used str2num and it still didnt work:
bridge1Weight = str2num(bridge1WeightInput);
dpb
dpb 2015-10-11
bridge1Load must be a cell array, not a double, then. A likely candidate to have caused that would be reading the data from a file via textscan.
The best solution relies somewhat on just what the form of the data are; how was it actually loaded/obtained and specifically, what does
whos bridge1Load
return?
Then we can look at "more better" ways to do the above as well...

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Anas Abou Allaban
Anas Abou Allaban 2015-10-11
Please ignore this rather silly question, I had to use str2double.....
  1 个评论
dpb
dpb 2015-10-11
OK, although I'dve thunk that'd given a message regarding cell strings, not just cell.
Anyway, as noted, "the Matlab way" for the above once you have the 2D array (matrix) is
maxload1=max(bridge1Load(:);
no loops needed. The {:} returns the array as a vector, hence the maximum will be found over all elements in the array, otherwise, max operates by column so one often sees such code as
maxload1=max(max(bridge1Load));
to do the same thing. (Try a small array of random values at the command line to see how it works).
You're not keeping track of the location at which the max occurs above; one would presume that also will be of some interest before you're done completely. For that, use the optional index returned by max and convert to the row/column position in the array via ind2sub
[maxload1,imx]=max(max(bridge1Load));
[rmax,cmax]=ind2sub(size(bridge1Load),imx);

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