How to run Fsolve using vectors

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Fotis
Fotis 2015-10-13
评论： BB 2021-12-4
Hi everyone. I am trying to run fsolve using vectors as inputs but it doesn't seem to work. My code is below. Do I have a syntax error?? I get x=[1 1 1 0.005348] as output. Seems that first 3 elements are just the same as initial condition. Any ideas?:
a = [2 1 3 4];
b = [-5 -10 -20 -30];
for i = 1:length(a)
F = @(x) ((log(x(i)^a(i)) - x(i)) - b(i));
x0=[1 1 1 1];
x = fsolve(F,x0,optimset('Display','none'));
end

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回答（1 个）

Torsten
Torsten 2015-10-13
a = [2 1 3 4];
b = [-5 -10 -20 -30];
F = @(x)log(x.^a)-x-b;
x0 = [1 1 1 1];
x = fsolve(F,x0,optimset('Display','none'));
Best wishes
Torsten.

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