Translation of a function

Question

Andrew Harris 2015-10-14

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编辑： John D'Errico 2015-10-14

This has to be simpler than I'm making it. I have a function f(x) = 1-abs(x) where -1<x<1 and f(x) = 0 otherwise. I want to evaluate it for a translation f(x-2) and f(x-3). In algebra I know this should just take the initial function graph and move it to the right, however evaluating it in MATLAB changes the function from a triangle to a straight line, and over the wrong range. Any ideas what I'm missing?

    f = @(x) 1-abs(x)
    x = linspace(-1, 1)
    figure
    plot(x, f(x))
    x1 = linspace(1, 3);
    x2 = linspace(2, 4);
    figure
    plot(x1, f(x-2))
    hold on
    plot(x2, f(x-3))

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Answer 1

John D'Errico 2015-10-14

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编辑：John D'Errico 2015-10-14

在 MATLAB Online 中打开

Try this modification instead. You almost had it right.

f = @(x) max(1-abs(x),0);
ezplot(f,-3,3)

ezplot(@(x) f(x-1),-3,3)

In your original function, when you translated it, you were seeing only one half of the abs function, and you were allowing it to go to -inf. The max that I added cuts off the function when it wants to go negative.