Nested function global variable
6 次查看(过去 30 天)
显示 更早的评论
function T = fun(theta)
global m
m = theta^2;
T = quad(@fun2,0,1)
end
function out = fun2(t)
out=( (1-m*t^2)*(1-t^2) );
end
I have the two functions above. When I call for fun, it does not seem to be working. I am new to Matlab so it would be greatly appreciated if someone could help my understanding. Thanks
0 个评论
采纳的回答
Thorsten
2015-10-15
编辑:Thorsten
2015-10-15
Add global m to your fun2; I also used point-wise multiplication and exponentiation to make it work.
function T = fun(theta)
global m
m = theta^2;
T = quad(@fun2,0,1)
end
function out = fun2(t)
global m
out=( (1-m*t.^2).*(1-t.^2) );
end
Alternatively, you could define fun2 as an anonymous function; note that here fun2 is already a function handle, so you have to pass with without the @ to quad:
function T = fun(theta)
global m
m = theta^2;
fun2 = @(t) (1-m*t.^2).*(1-t.^2)
T = quad(fun2,0,1)
end
更多回答(1 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!