nlms output problem. if i give the inputs as a). desired AOA = 20 . b). 1st interfer = 40 .c). 2nd interfer = -20 ..output for b) and c) are not coming correctly. please help with my code

Question

viswanadh raviteja 2015-10-29

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/251670-nlms-output-problem-if-i-give-the-inputs-as-a-desired-aoa-20-b-1st-interfer-40-c

编辑： viswanadh raviteja 2015-10-29

d = .5; 
N=6;
thetaS = input('   What is the desired users AOA (in degrees)?   ');
thetaI = input('   What is the 1st interferers AOA(in degrees)?   ');
thetaIs = input('   What is the 2nd interferers AOA(in degrees)?   ');
T=1E-3;
t=(1:100)*T/100;
it=1:100;
S=cos(2*pi*t/T);
thetaS = thetaS*pi/180;                  
I = randn(1,100); 
thetaI = thetaI*pi/180;  
Is = randn(1,100); 
thetaIs = thetaIs*pi/180;  
vS = []; vI = []; vIs = [];
i=1:N;
vS=exp(1j*(i-1)*2*pi*d*sin(thetaS)).';
vI=exp(1j*(i-1)*2*pi*d*sin(thetaI)).';
vIs=exp(1j*(i-1)*2*pi*d*sin(thetaIs)).';
w = zeros(N,1);     snr = 10;  
 X=(vS+vI+vIs);
Rx=X*X';
mu=1/(4*real(trace(Rx)))
wi=zeros(N,max(it));
for n = 1:length(S)
    x = S(n)*vS + I(n)*vI + Is(n)*vIs;
    y=w'*x;
      e = conj(S(n)) - y;      esave(n) = abs(e)^2;
      w = w + mu/(0.001+x'*x) * x.* conj(e) ;
      wi(:,n)=w;
      yy(n)=y;
  end
  w = (w./w(1));    % normalize results to first weight
theta = -pi/2:.01:pi/2;
AF_3 = zeros(1,length(theta));
for i = 1:N
    AF_3 = AF_3 + w(i)'.*exp(1j*(i-1)*2*pi*d*sin(theta));
end
figure
hold on
xlabel('AOA (deg)')
ylabel('|AF_n|')
plot(theta*180/pi,abs(AF_3)/max(abs(AF_3)),'b')
axis([-90 90 0 1.1])
set(gca,'xtick',[-90 -60 -30 0 30 60 90])
legend('NLMS')
grid on