how to measure the shortest distance from a point to the edge ?

8 次查看（过去 30 天）
Shan Kapoor
Shan Kapoor 2012-1-4
Hi All,
Can somebody help me how to measure the shortest length ( Perpendicular length) from the dots indicated inside black rectangle to the edge of the black portion on both sides in the following image ?? also, how to measure the shortest length between the points indicated in blue color??
https://picasaweb.google.com/116243239493929305987/January42012#5693806876116607234

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2012-1-6
I see the black band, and I see scattered white dots. I do not see any blue points?
The shortest distance from a point (x,y) to the edge of the black is
min([x, width-x, y, height-y])
  2 个评论
Shan Kapoor
Shan Kapoor 2012-1-7
Dear Walter,
Thank you your response...
I am very new to image analysis. I am sorry I do not know how to use the above function. here is my prolem to mathematically describe structures like below.
https://picasaweb.google.com/116243239493929305987/December292011#5694903096028938802
The two dots are the output of a simple matlab code to find the ultimate points ([trI,trJ] by the code below. and "tr2pkDists" are the distances from those points to the edges.
%---------------------------------------------------------
% Read the image and convert to BW mask of peaks
I_orig = imread('4.png');
figure, imshow(I_orig)
I = rgb2gray(I_orig);
BW_peaks = im2bw(I);
figure, imshow(BW_peaks)
% How far is every non-peak pixel from its nearest peak
maxDistsMask = imregionalmax(distFromPeaks);
[trI,trJ] = find(maxDistsMask);
trVals = I(maxDistsMask);
tr2pkDists = distFromPeaks(maxDistsMask)
I_norm = double(I)/double(max(I(:)));
figure, imshow(cat(3,I_norm,max(BW_peaks, I_norm),I_norm)), hold on
plot(trJ,trI,'.'),
% Now if we look at all of the maxdists in the image, how far away from
% peaks are they?
figure, plot(sort(tr2pkDists)), title 'Distribution of cusp spacing'
%-----------------------------------------------------------------------
as you can see, this is not enough as it does not give a total description.
right now I am here...
https://picasaweb.google.com/116243239493929305987/December292011#5694903944956708626
If I could do something like below, my issue is resolved...
https://picasaweb.google.com/116243239493929305987/December292011#5694903541436663602
ie, 1) find the shortest distance between the ultimate points.
2) find the shotest distances from point lying on the shrtest distance line from 1) to the edge of image ( to both sides, upper and lower)
and apply this method to images like below.
https://picasaweb.google.com/116243239493929305987/ImageAnalysis02#5691495061279679666
seek your suggestions.. Thanks you.
Shanoob

请先登录，再进行评论。

更多回答（1 个）

Image Analyst
Image Analyst 2012-1-5
Use bwdist(). The max of the output image returned by bwdist() is the distance to the closest boundary. Of course this is all a guess since your link doesn't work and I can't see your image. Or use bwboundaries() and run around the boundary coordinates using Pythagorean theorem to find the distance to some know, fixed coordinate.
  3 个评论
显示 1更早的评论
Image Analyst
Image Analyst 2012-1-7
I see you finally posted the link below. Since the dots are the ultimate eroded set, which you can get from
ultimateErosion = bwulterode(originalBW);
The distance from any point, including those at the center of your circles, is given by bwdist(). I'm really puzzled as to why you think bwdist doesn't work for irregularly shaped objects. Did you try it? It does work. Just try it.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Region and Image Properties 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by