Problem with Nested if statements

2 次查看（过去 30 天）
Aftab Ahmed Khan
Aftab Ahmed Khan 2015-11-9
编辑： Aftab Ahmed Khan 2015-11-9
Hi everyone, I am using nested if statements to perform a subsection of my project but i don't like the way i have implemented it. I am sure that there will be some optimum way of doing the following task, so to avoid so many if statements. Thank you so much.
if any(idcabs==[1 2 3 4])
if any(idabs==[1 2 5 6 9 10 13 14])
idbeam1=1;
else
idbeam1=3;
end
elseif any(idcabs==[5 6 7 8])
if any(idabs==[1 2 5 6 9 10 13 14])
idbeam1=3;
else
idbeam1=1;
end
elseif any(idcabs==[9 10 11 12])
if any(idabs==[1 2 3 4 5 6 7 8])
idbeam1=2;
else
idbeam1=4;
end
elseif any(idcabs==[13 14 15 16])
if any(idabs==[1 2 3 4 5 6 7 8])
idbeam1=4;
else
idbeam1=2;
end
end

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2015-11-9
You should consider using ismember()
  2 个评论
Aftab Ahmed Khan
Aftab Ahmed Khan 2015-11-9
编辑：Aftab Ahmed Khan 2015-11-9
Hi Walter, even if a consider ismember(), i will still need those nested If statements. It will be just a change of functions from any() to ismemeber(). Do you mean something like this just for the first part.
Aftab Ahmed Khan
Aftab Ahmed Khan 2015-11-9
id1=ismember(idcabs,C1)
id2=ismember(idabs,S1)
if ~isempty(id1) && ~isempty(id2)
idbeam1=1;
else
idbeam1=3;
end

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Whos 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by