cannot find the error in my code

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Mohammed Alqanber
Mohammed Alqanber 2015-11-10
编辑： Stephen23 2015-11-11
This is my code
function out=random_rayleigh(x,y)
msg = nargchk(0,2,nargin);
error(msg);
if nargin <1
y=1;
x=1;
elseif nargin <2
y=x;
end
array1=randn(x,y);
array2=randn(x,y);
out=sqrt(array1.^2+array2.^2);
no_of_samples=500;
mean_noise_level=10;
Detection_threshold_dB=[5.,6.,7.,8.,9.,10.,11.,12.,13.];
threshold_in_v=mean_noise_level.*10.0.^(Detection_threshold_dB/20.);
tota_samples=mean_noise_level/1.25*random_rayleigh(1,no_of_samples);
for jj=1:length(threshold_in_v)
total(jj)=sum(total_samples>threshold_in_v(jj));
end
fprintf('the constant false alarm rate for the threshold level is:');
for jj = 1:length(threshold_in_v)
fprintf('threshold(volts)=%5.1f dB Pfa=%14.5e', Detection_threshold_dB(jj),total(jj)/no_of_samples);
end
This is the error message I got
Maximum recursion limit of 500 reached. Use set(0,'RecursionLimit',N) to change the limit. Be aware that exceeding your available stack space can crash MATLAB and/or your computer.
Error in random_rayleigh

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回答（3 个）

Torsten
Torsten 2015-11-10
It seems you call random_rayleigh within random_rayleigh more than 500 times ...
Best wishes
Torsten.
Stephen23
Stephen23 2015-11-10
编辑：Stephen23 2015-11-11
Your function random_rayleigh calls itself on this line:
tota_samples=mean_noise_level/1.25*random_rayleigh(1,no_of_samples);
But there is not count-down or count-up to some limit, so there is no limit to how many times this function will call itself.
But considering that the output value tota_samples is not used, why are you calling this function inside itself anyway? If its output is not used, then why call it?
Thorsten
Thorsten 2015-11-10
Basically your function is
function out=random_rayleigh(x,y)
% some code
tota_samples=mean_noise_level/1.25*random_rayleigh(1,no_of_samples);
%more code
So if you call random_rayleigh, you end up in an endless recursion of calling random_rayleigh.

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