plotting maximal lyapunov exponent using ode45
6 次查看(过去 30 天)
显示 更早的评论
i m in need to plot the lyapunov exponent 'f vs lyapunov,' but i am unable to run the program due to some error in the program. can anyone pls help me to get the plot and any suggestions to make it perfect.
with kind regards
matlab codes:
clc
global f
for f=0.0:0.1:30
f
initialx(1)=0.0100;initialx(2)=0.01;
lyap(1)=.01;
[t,x]=ode45('loreeneq',0:1:500,[initialx(1),initialx(2)]);
lyap1=lyap([t,x(:,1)]);
plot(f,lyap1,'r');
hold on
drawnow
end
xlabel ('f');ylabel('lyap')
--------------------------------------------------------------------------
function dxdt=loreeneq(t,x)
global r
dxdt1=10*(x(2)-x(1));
dxdt2=(r*x(1))-x(2)-(x(1)*x(3));
dxdt3=(x(1)*x(2))-(2.67*x(3));
dxdt=[dxdt1;dxdt2;dxdt3];
2 个评论
Walter Roberson
2012-1-9
It is faster for us if you show us the error message and the line it is complaining about.
采纳的回答
Walter Roberson
2012-1-9
In the top portion you have "global f", but you do not use "f" in the other portion. In the bottom portion you have "global r" but you do not use "r" in the other portion.
"global" shares by variable name. There is not just one global variable available. If you want to use the value of f in the bottom routine and you want to pass it via a global then you need to use "global f" in the bottom routine and reference f there instead of r.
If that is what you are trying to do then there are better approaches, which the ode45 documentation links to when it says to see the documentation on "parameterizing functions"
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrix Computations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!