3>2>1 returns logical 0?
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When I run 3>2>1 it returns logical 0 (false). Sorry if its a basic question but I can't understand how this is not true.
采纳的回答
The basic problem is that you are attempting two logical relations simultaneously: MATLAB's relational operators are binary operators, so they only support one comparison at once. In summary:
X<A<Y % is NOT valid for comparing A against X and Y
X<A & A<Y % This compares A with both X and Y
In MATLAB logical relational operators follow the standard rules of operator precedence. Look at this example carefully:
>> 3<4<2
ans =
1
The output is true, so does this mean that 4<2 ? Of course not, we just have to remember the operator precedence rules, just like in high school. This is evaluated according to those rules as:
>> (3<4)<2
ans =
1
where
>> 3<4
ans =
1
So 3<4<2 is actually equivalent to 1<2, which is of course very true:
>> 1<2
ans =
1
更多回答（2 个）
Guillaume
2015-11-30
You cannot chain comparisons. You have to use logical operators.
3>2>1
is the same as
(3>2) > 1
which evaluates to
true > 1
which is false since true is the same as 1.
To do what you want:
3>2 && 2>1
I think the compiler probably solves this:
(3>2)>1
ans =
0
i.e 1>1= 0
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