How to determine array equality ?

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x y
x y 2015-11-30
评论： Guillaume 2015-11-30
hy I want to in main while cycle search for point with random searching 'robot'. If the robot see the point what is not in the list, then should put the coordinate to the list...if this point does not contain. I can't figure out how to comparate... I tried different way, the last what I did is this,but I need something like do in for loop,what is going through the matrix rows.
templist = [1 2 0
2 2 0
45 5 0
4 5 1
7 85 0
4 5 1]
newcordinate = [ 4 5 ]
LIST = [];
% sum( [zoznam(:,1) zoznam(:,2)]' )
if sum(newcordinate') == sum( [templist(:,1) templist(:,2)]' )
display('do nothing')
else
templist(end+1)= newcordinate(1,2);
templist(end+1)= newcordinate(1,1);
templist(end+1)= 0;
LIST = reshape(templist,3,[])'
end
the third element is need in the further to determine is the coordinate is used or not

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Guillaume
Guillaume 2015-11-30
Possibly, this is what you want:
templist = [1 2 0
2 2 0
45 5 0
4 5 1
7 85 0
4 5 1]
newcoordinate = [4 5]
if ismember(newcoordinate, templist(:, [1 2]), 'rows')
display('do nothing');
else
templist(end+1, :) = [newcoordinate, 0];
end
  2 个评论
x y
x y 2015-11-30
编辑：x y 2015-11-30
Yes, Thank you :)
in the begining the list is empty, so I need to set
templist= [0 0 0]
and at 'templist(end+1, :) = [newcoordinate, 0];'
I have error,
Dimensions of matrices being concatenated are not consistent.
Guillaume
Guillaume 2015-11-30
It would be better to initialise templist with
templist = zeros(0, 3);
I cannot reproduce your second error. Are you sure that newcoordinate is a 1x2 vector?

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