Create Minesweeper Like Game

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Krish Desai
Krish Desai 2015-12-1
评论： Guillaume 2015-12-1
I create this board with my code:
1 2 3 4 5
1x x x x x
2x x x x x
3x k x x x
4x x x k x
5x x x x x
I want to replace the board above with the board below, that is all the 'k'='*' and any values surrounding k have a counter.
1 2 3 4 5
10 0 0 0 0
21 1 1 0 0
31 k 2 1 1
41 1 2 k 1
50 0 1 1 1
How would I go about doing this?
  2 个评论
Walter Roberson
Walter Roberson 2015-12-1
I do not understand about 'k'='*', and it is not clear why the x became 0 in places that are not surrounding k.
Image Analyst
Image Analyst 2015-12-1
k is where a bomb resides. The other numbers are the number of 8-connected bombs that are next to that location. For example, row 3, column 3 is next to 2 bombs, so it's a 2. Row 3, column 4 is next to only one k, so it has a value of 1. Same as in the minesweeper game.

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采纳的回答

Image Analyst
Image Analyst 2015-12-1
Just use conv2() to count the bombs:
gameBoard = [...
'0' '0' '0' '0' '0'
'1' '1' '1' '0' '0'
'1' 'k' '2' '1' '1'
'1' '1' '2' 'k' '1'
'0' '0' '1' '1' '1']
% Find the bombs.
bombLocations = gameBoard == 'k'
% Sum up the bombs in a surrounding 3x3 window around each pixel.
nearbyBombs = conv2(double(bombLocations), ones(3), 'same')
% Create a new board that is characters and instead of numbers.
newBoard = num2str(nearbyBombs, '%1d')
% Replace the bomb locations with the letter k.
newBoard(bombLocations) = 'k'
You'll see:
gameBoard =
00000
11100
1k211
112k1
00111
bombLocations =
0 0 0 0 0
0 0 0 0 0
0 1 0 0 0
0 0 0 1 0
0 0 0 0 0
nearbyBombs =
0 0 0 0 0
1 1 1 0 0
1 1 2 1 1
1 1 2 1 1
0 0 1 1 1
newBoard =
00000
11100
11211
11211
00111
newBoard =
00000
11100
1k211
112k1
00111

更多回答（1 个）

Guillaume
Guillaume 2015-12-1
Please, use valid matlab syntax in your question, so we don't have to guess if the input is a cell array, a char array, or something else, and whether the spaces and headers are embedded in the matrix or not
Possibly:
in = ['xxxxx';
'xxxxx';
'xkxxx';
'xxxkx';
'xxxxx'];
%step 1: convert the input matrix into an array of 0 and 1, 1 where k is present
%if your input matrix is a different format, you'll have to figure how to do it on your own
inaslogical = in == 'k';
%step2: convolve the array of 0 and 1 with an array of 1:
out = conv2(double(inaslogical), ones(3), 'same')
  2 个评论
Krish Desai
Krish Desai 2015-12-1
Cell array, spaces and headers are embedded I believe
function board = makeboard(size)
board = cell(size+1,size+1);
% initialize the board
for i=1:size+1
for j=1:size+1
if i==1
if j<=size
board{i,j+1} = j;
board{j+1,i} = j;
end
elseif j==1
elseif rand < 1/5
board{i,j}='k';
else
board{i,j}= 'x';
end
end
end
end
Guillaume
Guillaume 2015-12-1
Note: don't use the name size for a variable as you won't be able to use the extremely useful size function.
A more efficient way to generate your board:
function board = makeboard(boardsize)
symbols = 'xk';
playarea = num2cell(symbols(1 + (rand(boardsize) < 1/5)));
header = num2cell(1:boardsize);
board = [{[]}, header; header', playarea];
end
The gist of my answer (and IA's answer) still stands. You need to convert your play area into a logical array, where 1 stands for a mine. Then convolve with a square of 1 to get the number of neighbours.
With the given format:
ismine = cell2mat(board(2:end, 2:end)) == 'k';
neighbourcount = conv2(double(ismine), ones(3), 'same');
neighbourcount = num2cell(neighbourcount);
neighbourcount(ismine) = {'k'};
newboard = board;
newboard(2:end, 2:end) = neighbourcount;

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