Resort struct elements by one field values

4 次查看（过去 30 天）
REN
REN 2011-3-6
Hello,
In a struct
A = struct('f1', [some values], 'f2', [some values])
Can we resort elements of A by increasing order in f1?
For example:
A = struct('f1', [some values], 'f2', [some values])
A.f1 is a 1 X 5 double value [3, 4, 1, 2, 5]
A.f2 is 1 X 5 double value [val 3, val 4, val 1, val 2, val 5]
How to create another struct B as
B = struct('f1', [1 , 2, 3, 4, 5], 'f2', [val 1, val 2, val 3, val 4, val 5])?
  1 个评论
Walter Roberson
Walter Roberson 2011-3-6
One can re-sort in Matlab, and one can resort -to- Matlab, but I didn't know of any Matlab Resort ;-)

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采纳的回答

Matt Tearle
Matt Tearle 2011-3-6
Would this do it?
a.foo = [3, 4, 1, 2, 5];
a.bar = {'a','b','c','d','e'};
% assuming b already exists
b = a;
% reorder b
[sortfoo,idx] = sort(a.foo);
b.foo = sortfoo;
b.bar = b.bar(idx)

更多回答（1 个）

Giovanni Soldi
Giovanni Soldi 2011-3-6
Try in this way:
B = struct('f1',sort(A.f1),'f2',sort(A.f2));
  2 个评论
REN
REN 2011-3-6
but in f2 val 3, val 4, val 1, val 2, val 5 can not be sorted
f2 can be only sorted according to value in f1
REN
REN 2011-3-6
even f2 can be sorted by increasing oder,
if try
B = struct('f1',sort(A.f1),'f2',sort(A.f2));
a result maybe
B.f1 = [1 2 3 4 5]
B.f2 = [val 2 val 3 val 4 val 5 val 1]
because val 2 < val 3 < val 4 < val 5 < val 1

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