I cant CREATE array the rand() in for loop..... Firstly, generate 72 bit binary number in 20 times. After, i need use the second, tenth or fifth generated random binary number.

2 次查看（过去 30 天）
Mahmut Yasak
Mahmut Yasak 2016-1-6
评论： Mahmut Yasak 2016-1-6
But, error:
In an assignment A(I) = B, the number of elements in B and I must be the same.
Error in ga_function2 (line 9)
random_chromosome(popSize) = round(rand(1, 72));
random_chromosome = [1;20];
for popSize = 1 : 1 : 20
random_chromosome(popSize) = round(rand(1, 72));
end

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2016-1-6
编辑：Stephen23 2016-1-6
Because popSize is scalar, the code
random_chromosome(popSize)
refers to one element of the array random_chromosome, but rand(1, 72) is an array with 72 elements.
You are trying to fit seventy-two elements into the space of one element in a matrix, which obviously does not fit and causes the error. One better solution would be to avoid that inefficient loop altogether:
X = randi(2,20,72)-1;
produces a matrix X of size 20x72, where each row corresponds to one of your "random binary number". For example the second number is simply the second row:
X(2,:)
You can learn more about basic MATLAB usage by doing these tutorials:
http://www.mathworks.com/help/matlab/getting-started-with-matlab.html

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by