This code is a good example of why badly formatted code causes so many problems. Why do beginners avoid using the inbuilt editor's default indenting? When the code is indented properly, then some of the problems become clearer:
d=input('waht');
if d==1
fprinf('d=%f',d);
else
if d==2
fprinf('d=%f',d);
end
else
if d==3
fprinf('d=%f',d);
end
else
if d==4
fprinf('d=%f',d);
end
end
Do you see that the second and third else statements do not correspond to any if statement? This is also clearly highlighted in the MATLAB editor, with orange underline indicating a syntax error. Click on the line to get info about the error. Note that MATLAB supports elseif, but else if has no special meaning.
It is likely that the author really intended something more like this (using switch would be even neater):
d=input('waht');
if d==1
fprinf('d=%f',d);
elseif d==2
fprinf('d=%f',d);
elseif d==3
fprinf('d=%f',d);
elseif d==4
fprinf('d=%f',d);
end
Although given that every case is identical, the whole code could be replaced with this anyway:
d=input('waht');
fprinf('d=%f',d);
The other problems will be discovered shortly, such as fprintf being spelled incorrectly.
