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How can I compute the following formular recursive ?

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Fox
Fox 2016-1-13
评论： Pavithra Ashok Kumar 2016-1-21
x1=b(1)+ b(2)*x0+resrd2(1,:); % b1 and b2 are scalars x(0) also resrd2 is a matrix of 743x1
x2=b(1)+ b(2)*x1+resrd2(2,:);
x3=b(1)+ b(2)*x2+resrd2(3,:);
How can I solve this ? My Problem here is, that the x values should change recursively and that I want to get the fitting values from the resrd2. In the end the goal is to get a matrix of 743x1. Can somebody please help me here ?
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Fox
Fox 2016-1-13
编辑：Fox 2016-1-13
Problem is that I've now the resrd in addition and it doesn't work with the structure before. I've the formular to solve the problem without resrd.
xm = a*(1-b.^m)/(1-b) + b.^m*xx0;
When I've now the resrd, I can transform this to:
for i=1:743
xx=a+resrd(i,:);
xm = xx*(1-b.^m)/(1-b) + b.^m*xx0;
end
However my solutions are wrong. You know a way how to fix this or another approach to solve this problem ?
Pavithra Ashok Kumar
Pavithra Ashok Kumar 2016-1-21
%Call this function with x(n)
function out = x(index)
if index == 1
return x(0);
else
out = a+b*x(index-1) + resrd(index-1);
end
Collecting the out values will give the array you are looking for. Hope this helps.

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