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index out of bound

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sweta arya
sweta arya 2016-1-20
关闭： MATLAB Answer Bot 2021-8-20
intial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
y =zeros(30,1);
y = datasample(intial_image,30);
disp(y(2,1));
size3=0;
nBins=8;
Nind=0;
h1=0;
count=0;
for i=1:30
if(numel(y)==30)
jpgFileName = strcat('C:\Users\priya\Desktop\Fashion Photography\',num2str(y(i)), '.jpg');
I= imread(jpgFileName);
[row,col,m]=size(I);
size3=size3+ row*col;
count=count+1;
end
giving error:
can not access y(2,1) because numel(y)=1.
  2 个评论
Stephen23
Stephen23 2016-1-20
Please show us all of the error message. This means all of the red text.
Stephen23
Stephen23 2016-1-20
The code needs to be simplified. Replace this:
initial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
with this:
initial_image = (1:180).';
There is no point in preallocating y like this:
y =zeros(30,1);
because it is completely reallocated on the very next line:
y = datasample(...)

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回答（1 个）

Walter Roberson
Walter Roberson 2016-1-20
Whatever
datasample(intial_image,30)
is, it is resulting in a scalar.
What is the result of
which -all datasample
? Is it from the Statistics Toolbox or does it resolve to one of your own routines?

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