Discrete time system difference equation

11 次查看(过去 30 天)
I want to know what is the method to solve such a problem in matlab. Considering a discrete time system difference equation as follows:
How do I compute the value of y @ time k=5. when the input sequence is U=[1 -2 3 -4] and the initial conditions are Y(1)=1 , y(2)=1.
y=??? Please ; I want information regarding such a problem . I searched everywhere but didn't help me properly. If you can explain the steps of the solving it will be very helpful.... Thanks in advance :)

采纳的回答

Torsten
Torsten 2016-2-11
u=[1 -2 3 -4];
y(1)=1;
y(2)=1;
for k=2:4
y(k+1)=-2*y(k)+3*y(k-1)+1.5*u(k)+4*u(k-1);
end
y(5)
Best wishes
Torsten.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Numerical Integration and Differentiation 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by