Is matlab not considering L Hospital's rule, while calculating limits? Becoz there r two different answers of the function f=(1 - (cos(x)))/((2* ((x^3)))* sin(x)).

6 次查看（过去 30 天）

显示更早的评论

Shivangi Chauhan 2016-2-11

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/267634-is-matlab-not-considering-l-hospital-s-rule-while-calculating-limits-becoz-there-r-two-different-a

评论： Torsten 2016-2-11

采纳的回答： Torsten

Is matlab not considering L Hospital's rule, while calculating limits? Becoz there r two different answers of the function f=(1 - (cos(x)))/((2* ((x^3)))* sin(x)). Using matlab it is 'inf' and using L hospital rule by hand calculation, it is (-1/48). Which one is correct?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Torsten 2016-2-11

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/267634-is-matlab-not-considering-l-hospital-s-rule-while-calculating-limits-becoz-there-r-two-different-a#answer_209402

Plot the function and you'll see that MATLAB's answer is correct.

The function behaves like 1/x^2 near x=0.

Best wishes

Torsten.

2 个评论
显示无隐藏无

Shivangi Chauhan 2016-2-11

But i solve by hand, without plotting the functions, i am getting different value (near to matlab value). Can i get exact same value?

Torsten 2016-2-11

Which value are you talking about ?

(1-cos(x))/(2*x^3*sin(x)) ~ (1-(1-x^2/2))/(2*x^3*x) = 1/(4*x^2)

near x=0.

We have to see your calculations to point out the error you made.

Best wishes

Torsten.

请先登录，再进行评论。

更多回答（0 个）

请先登录，再回答此问题。

类别

MATLAB Language Fundamentals Data Types Data Type Identification

在 Help Center 和 File Exchange 中查找有关 Data Type Identification 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Translated by