What does this message mean in matlab ?

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mar vouz 2016-4-26

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评论： John D'Errico 2016-4-26

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So I created the following code :

    % code
 x=0;
h=0.001;
tol_root=1e-05;
tol_x=1e-05;
for i = 1:1:50
f=@(x) x.^2 + 0.16*x -0.237;
fpl=@(x) f(x+h);
fout=@(x) f(x-h);
df=@(x) (fpl(x)-fout(x))/(2*h);
if df(x)==0 then
if f(x)<=tol_root 
i=51;
else
x=x+h
end
end
xnew=x-f(x)/df(x);
if abs (xnew-x)<= tol_x 
e(i)=@(x) abs(xnew-x)
i=51
else 
x=xnew
end
end
xroot=xnew
And it actually gives me seven roots.But also it gives me this message:
* _The following error occurred converting from function_handle to double:
Error using double
Conversion to double from function_handle is not possible.*
why?