How can I change a row data in Table, Uitable?

Question

brigitte duran 2016-4-29

0
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I have a table and I can not change my values in my second row, I don't understand..Can you explain please? My code:

Initialize d = 1.12; % I want remplace by %d = [0;1.12;1.12;1.15;1.15;1.15;1.20;1.20;1.20;1.30]

dt = 10;

numFluide = 1; NbreFluide = 10; fluide = 0:1:NbreFluide;

si = 0.30;

%% initialisation variables. t = 0

      vol_inj = 0;
      MatI = zeros(length(fluide),7);
      MatI(1,1) = 0; % colonne1: Numero de fluide
      MatI(1,2) = 0; % colonne2: densité  
      MatI(1,3) = 0; % colonne3: volume de fluide qui dépend du debit
      MatI(1,4) = 0; % colonne4: mdTop
      MatI(1,5) = 0; % colonne5: mdBottom
      MatI(1,6) = 0; % colonne6: hauteur
      MatI(1,7) = 0; % pression hydrostatique
      %%Incrementation: t + dt
          for k = 2:length(fluide)
              vol_inj = vol_inj + (Qin * dt); % vol_inj devient apres un fluide  
              for j = 1:length(fluide)-1
                  MatI(j,1)= MatI(j+1,1);
                  MatI(j,2)= MatI(j+1,2);
                  MatI(j,3)= MatI(j+1,3);
                  MatI(j,4)= MatI(j+1,4);
                  MatI(j,5)= MatI(j+1,5);
                  MatI(j,6)= MatI(j+1,6);
                  MatI(j,7)= MatI(j+1,7);
              end
              MatI(length(fluide),1) =(k-1)*numFluide ;
              MatI(length(fluide),2) = d ; %HERE DOESN'T WORK WHEN I REMPLACE
              MatI(length(fluide),3) = vol_inj ;
              MatI(1,4) = 0 ;
              MatI(1,5) = 0 ;
                  for i = 2 :length(fluide)-1 
                      MatI(2,4)= 0
                      MatI (i+1,5) = MatI(i+1,4) + vol_inj 
                      MatI (i+2,4) = MatI(i+1,5) 
                  end 
              MatI(length(fluide),6)= abs(MatI(i,4) - MatI(i,5)) ;%THESE PART DOESN4T WORK AND I DON't UNDERSTAND...
              MatI(length(fluide),7)= d.*9.81.*MatI(length(fluide),6);
          end
        set(handles.uitable1,'Data',MatI);
Thanks