how to split and transpose a cell array?

1 次查看(过去 30 天)
Hi !! I have the next cell composition (30*1 size)
What I want to do is to split it first, according to the "," so each different number has to occupy a diffierent column. Like this:
After this, I want to transpose all the numbers, so I want to have a final matrix size (7*30)
Can anyone help me to solve this?
Thanks in advance!

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-4-29
a={'12,13,14,45';'4,8,nan,nan';'450,2,14,nan'}
out=cell2mat(cellfun(@(x) str2num(strrep(x,',',' ')),a,'un',0))'
  4 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2016-4-29
编辑:Azzi Abdelmalek 2016-4-29
This is not a problem, you know how to transpose a matrix?
out=out'
Now, for your previous comment, please post an example. It seems that your data are not similar to my example.
Viridiana  Torres
Viridiana Torres 2016-4-30
Thanks Azzi, these are some of the components in my a (as you call it in your example):
[199001021000.000,199001021005.000,199001021010.000,199001021015.000,199001031004.000,199001031009.000,199001031014.000]
[199001021001.000,199001021006.000,199001021011.000,199001031000.000,199001031005.000,199001031010.000,199001031015.000]
[199001021002.000,199001021007.000,199001021012.000,199001031001.000,199001031006.000,199001031011.000,NaN]
[199001021003.000,199001021008.000,199001021013.000,199001031002.000,199001031007.000,199001031012.000,NaN]

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Characters and Strings 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by