I get the following error in Newton Ralphson code?Can any one predict the mistake?If i use RETURN instead of break at last(21 line),then error "Not enough input arguments" appears as shown in image.

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Machine Learning Enthusiast
评论： Machine Learning Enthusiast 2016-5-19
f
function [x,iter]=newton(x0,f,fp)
% newton-raphson algorithm
N = 100; eps = 1.e-5; % define max. no. iterations and error
maxval = 10000.0; % define value for divergence
xx = x0;
while (N>0)
xn = xx-f(xx)/fp(xx);
if abs(f(xn))<eps
x=xn;iter=100-N;
return;
end;
if abs(f(xx))>maxval
disp(['iterations = ',num2str(iter)]);
error('Solution diverges');
break;
end;
N = N - 1;
xx = xn;
end;
error('No convergence');
break;
% end function

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回答（1 个）

Walter Roberson
Walter Roberson 2016-5-17
编辑：Walter Roberson 2016-5-17
You cannot just run that code by giving its name newton . You need to supply the three parameters. For example,
newton(12.345, @(x) sin(x) + 3/4, @(x) cos(x))
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Walter Roberson
Walter Roberson 2016-5-18
You would not rewrite the code: you would give a command at the command line like I show.
You could write a second .m file that contained those commands, if you wanted.
Machine Learning Enthusiast
Machine Learning Enthusiast 2016-5-19
i want to ininiate the iterative procedure by following equation, where i represents the iteration number: xi+1 = xi - f(xi)/f'(xi). After each iteration the program should check to see if the convergence condition, namely, f(x i+1)<ε,

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