isjava not correct?

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Daniel
Daniel 2016-5-18
评论： Daniel 2016-5-18
When I run the following code:
fH = figure;
textAreaHandle = javaObjectEDT('javax.swing.JTextArea');
scrollPaneHandle = javaObjectEDT('javax.swing.JScrollPane', textAreaHandle);
[javaHandle,matlabHandle] = javacomponent(scrollPaneHandle,[20,20,300,50],fH);
I get a figure with a java text area. When I look at the value of javaHandle it is the following:
javaHandle =
javahandle_withcallbacks.javax.swing.JScrollPane
When I run the isjava command on javaHandle, it returns a false, which is incorrect.
>> isjava(javaHandle)
ans =
0
I am wondering how can I fix this so that isjava returns true when run with this javaHandle variable? Is there another function I can use?
I am running 2015b
Thanks in advance

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采纳的回答

Walter Roberson
Walter Roberson 2016-5-18
javacomponent is not a documented routine, and the output of it is not specifically a java object (it is a handle to a component, but the handle could be a MATLAB handle.)
You can get the java object by using the java method on the javaHandle
  1 个评论
Daniel
Daniel 2016-5-18
Thank you! The following code returned what I wanted
>> isjava(javaHandle.java)
ans =
1

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