how to find and replace corresponding matri

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Triveni
Triveni 2016-5-19
编辑： VBBV 2023-7-26
a1{:}
ans =
73.3333 50.0000
66.6667 50.0000
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
ans =
Empty matrix: 0-by-2
i need to find index for non zero cell array, and convert in into mat.

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回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2016-5-19
编辑：Azzi Abdelmalek 2016-5-19
idx=celfun(@isempty,a1)
a1(idx)=[]
out=cell2mat(a1)
Andrei Bobrov
Andrei Bobrov 2016-5-19
out = cat(1,a1{:})
Guillaume
Guillaume 2016-5-19
编辑：VBBV 2023-7-26
idx = find(~cellfun(@isempty, a1)); %index of non empty cell
assert(numel(idx) == 1, 'There are more or less than 1 empty cell')
out = a1{idx}; %get content of cell, which is a matrix in your case

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