find index of cells containing other cells
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Hello,
I have a cell A of a size 1x9 and each of the 9 cells contains a cell 1xNumber, where Number is different for each of the 9 cells. E.g A{1,5} contains 1x100 cell and e.g A{1,5}{1,44} contains a number: 0.842. Now, I want to find the position of a fixed number, let's say 0.842. I want to search within all the cells. I checked manually and the number 0.842 is A{1,5}{1,44}. So as an output I want matlab to give me the numbers 5 and 44.
I tried with:
index = find([A{:}] == 0.824);
I'm getting an error:
Undefined function 'eq' for input arguments of type 'cell'.
I guess it's because my cell A contains cells...
Any help appreciated,
Thank you
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采纳的回答
Image Analyst
2016-5-22
I don't know why you don't just avoid the problem in the first place. I don't see any reason why the data in the cells needs to also be cells. Why not use just regular numerical arrays? So the cells contain arrays of doubles instead of other cells?
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更多回答(2 个)
Azzi Abdelmalek
2016-5-21
编辑:Azzi Abdelmalek
2016-5-21
A=arrayfun(@(x) randi(5,1,randi(10)),1:9,'un',0) % Example
m=3 % Looking for 3 in each cell
indices=cellfun(@(x) find(ismember(x,m)),A,'un',0)
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Azzi Abdelmalek
2016-5-21
Maybe I used a bad Example, try this
A=arrayfun(@(x) num2cell(randi(5,1,randi(10))),1:9,'un',0) % Example
m=3 % Looking for 3 in each cell
indices=cellfun(@(x) find(ismember([x{:}],m)),A,'un',0)
Andrei Bobrov
2016-5-21
编辑:Andrei Bobrov
2016-5-21
A1 = cellfun(@(x)[x{:}]',A,'un',0);
A1(cellfun(@isempty,A1)) = nan;
m = cellfun(@numel,A);
ii = cumsum(m);
i1 = ii + 1;
z = zeros(ii(end),1);
z(ii - m + 1) = 1;
zz = cumsum(z);
y = ones(ii(end),1);
y(i1(1:end-1)) = 1 - m(1:end-1);
i2 = cumsum(y);
ind = [zz, i2];
A2 = cat(1,A1{:});
out = ind(A2 == 0.824,:);
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