How can I compute the resolution of a triangular mesh ?

Question

jiji hr 2016-5-30

0
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https://ww2.mathworks.cn/matlabcentral/answers/286445-how-can-i-compute-the-resolution-of-a-triangular-mesh

评论： jiji hr 2016-6-8

Hi,

I want to compute the resolution of a 3D triangular mesh, that is defined as the median of the length of all edges in this mesh. I have an .obj file that contains vertices and faces, and after extracting them in 2D arrays(vertex, face):

function tabMedian = ComputeMedian_jihad( vertex, face )
  %COMPUTEMEDIAN_JIHAD Summary of this function goes here
  %   Detailed explanation goes here
    tabMedian = zeros(1,34817);  
    j = 0;  
    for i = 1 : size(face,1)
        d1 = (vertex(face(i,1),1) - vertex(face(i,2),1)) * (vertex(face(i,1),1) - vertex(face(i,2),1)) + (vertex(face(i,1),2) - vertex(face(i,2),2))*(vertex(face(i,1),2) - vertex(face(i,2),2)) + (vertex(face(i,1),3) - vertex(face(i,2),3))*(vertex(face(i,1),3) - vertex(face(i,2),3));
        d1 = sqrt(d1);
        d2 = (vertex(face(i,2),1) - vertex(face(i,3),1))^2 + (vertex(face(i,2),2) - vertex(face(i,3),2))^2 + (vertex(face(i,2),3) - vertex(face(i,3),3))^2 ;
        d2 = sqrt(d2);
        d3 = (vertex(face(i,3),1) - vertex(face(i,1),1))^2 + (vertex(face(i,3),2) - vertex(face(i,1),2))^2 + (vertex(face(i,3),3) - vertex(face(i,1),3))^2 ;
        d3 = sqrt(d3);
        j = j + 1;
        tabMedian(j)   = d1;
        tabMedian(j+1) = d2;
        tabMedian(j+2) = d3;   
    end

so what i did is to compute the distance between each 2 vertices from the 3 ones that constain the face. then I stok them in an array.Then I use the matlab function median on the table returned by my function. But the problem here is that there will be a (number of vertices) redundancy.

So I would be grateful if you tell me if this is the good way to compute the resolution of the mesh, and how can I eliminate those redundancies.