Does NaN used in confusion matrix affects results?

2 次查看(过去 30 天)
I have used confusion matrix and for making two matrices of equal dimensions I had used NaN but is it wise to use that? for example: A= [2 3 7 ]; B= [3 4 NaN]; C= A+B; C= 5 7 NaN I am getting where result should have been [5 7 7] according to me.Can anyone help? Thanx in advance.
  3 个评论
Ekta Sharma
Ekta Sharma 2016-6-15
Sir actually 0 is one the value in my matrix as I am using chain code,in that we have directions from 0 to 7.
Ekta Sharma
Ekta Sharma 2016-6-15
Is there anything else we can do for making two matrices equal in length?

请先登录,再进行评论。

采纳的回答

Chad Greene
Chad Greene 2016-6-16
Here's one way:
C = nansum([A; B])
C =
5 7 7
  2 个评论
Ekta Sharma
Ekta Sharma 2016-6-17
Sir may I know if I will keep using NaN in one of the matrices for making two matrices of equal dimensions.Will confusion matrix results such as true positive,false positive,true negative,false negatives values will get affected or not?
Chad Greene
Chad Greene 2016-6-17
Using NaN as a place filler is often the best way to do it. The reason 1+NaN=NaN is because Matlab doesn't what the answer is if you add a number to something that is not a number. But the nansum function and its sisters (nanmean, nanmedian, etc) are available to simply ignore NaNs the way you want.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by