Hello Luis,
Consider you have LFHD.txt file having 50,000 lines of code.
Keep it in your current directory and run following code:
1. Following code is to read the txt file and store its content into array variable " data
clear all;
count = 1;
fid = fopen('LFHD.txt.txt');
tline = fgetl(fid);
while ischar(tline)
if (tline ~= -1)
data(count,:) = {tline};
else
data(count,:) = {''};
end
count = count + 1;
tline = fgetl(fid);
end
fclose(fid);
2. Now, use following code to serach the row number for your specific name (e.g. LFHD)
for i = 1:length(data)
if ~isempty(strfind(data{i},'LFHD'))
rowNumber = i;
break;
else
if (i==length(data))
msgbox('No data found');
end
end
end
3. after running the above codes, if you check for variable "*rowNumber*", it will give you the row number in which your specific name is present.
Note: This code gives very first row number in which the specific name is present.
for example: if row 5 and 8 both having the specific Name (i.e. LFHD) then this code will give you the answer 5 and it will break the loop.
4. for your second point for location: First tell me how you calculated the value 3 for LFHD, so that I can give you the code for it.
5. with following code, you can find the location for LFHD.
location = strfind(data{i},'LFHD');
but, it gives answer as 6 and not 3,
it is because it is considering 1 for TAB, 2 for M, 3 for S, 4 for 1, 5 for :(colon) and 6 for LFHD..
If value 6 is correct then keep this line of code for 'location' just before 'break' statement.
