How to apply for loop for cell arrays?

Question

Ali Y. 2016-6-16

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/290257-how-to-apply-for-loop-for-cell-arrays

评论： Ali Y. 2016-6-16

I have a matrix that I want dividing it to n matrices, say n = 2, and do some operations along their lengths. The second chain of ‘for’ loops does what I need when there is one matrix, as in the case of the parent matrix (a). But I can’t apply same procedure for the two cell arrays I have.

clear all
clc
a =(1000-0).*rand(10,2)+0 ;
[r,c] = size(a) ;
mina = [1 7] ;
maxa = [6 10] ;
b = cell(numel(mina),1) ;
for o = 1:numel(mina)
    b{o} = a(mina(o): maxa(o),:);
end
max_a= zeros(r,c);
for i = 1:r
    for j = 1:c
        max_a(i,j) = max(a(1:i,j)) ;
    end
end

This following lines was what I tried before but it doesn’t work.

for u = 1:numel(mina)
    b2(1:maxa(u),:) = cell2mat(b(u)) ;
    for i2 = mina(u):maxa(u)
        for j2 = 1:c
            max_a {u} = max(b2(1:i2,j2)) ;
        end
    end
end

2 个评论
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Guillaume 2016-6-16

With your given example, can you show what the output of your last loop should be, as I've no idea what you're trying to do with it.

Guillaume 2016-6-16

在 MATLAB Online 中打开

Note that if you have a recent version of matlab, your first max_a is simply:

max_a = cummax(a);

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Answer 1

Azzi Abdelmalek 2016-6-16

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/290257-how-to-apply-for-loop-for-cell-arrays#answer_225697

在 MATLAB Online 中打开

a =(1000-0).*rand(10,2)+0
[r,c] = size(a)
mina = [1 7] ;
maxa = [6 10] ;
b = cell(numel(mina),1) ;
for o = 1:numel(mina)
  b{o} = a(mina(o): maxa(o),:);
end
for k=1:numel(b)
  bb=b{k};
  [r,c]=size(bb);
  max_a= zeros(r,c);
  for i = 1:r
      for j = 1:c
          max_a(i,j) = max(a(1:i,j)) ;
      end
  end
  max_b{k}=max_a
end