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How to simplify matrix expression

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cniv_we
cniv_we 2016-6-21
评论： cniv_we 2016-6-21
I have following matrix expression:
y_ = zeros(5000,10);
y_(1:500,10) = 1;
y_(501:1000,1) = 1;
y_(1001:1500,2) = 1;
y_(1501:2000,3) = 1;
y_(2001:2500,4) = 1;
y_(2501:3000,5) = 1;
y_(3001:3500,6) = 1;
y_(3501:4000,7) = 1;
y_(4001:4500,8) = 1;
y_(4501:5000,9) = 1;
y = y_;
How do I simplify this code under 2 or 3 lines? At the end I just want to have a matrix Y containing 5000x10 elements.
  2 个评论
cniv_we
cniv_we 2016-6-21
I think loop is enough. I tried this:
y = zeros(5000,10);
y(1:500,10) = 1;
j = 500;
for i=1:9
j = 500;
y(i*j+1:(i+1)*j,i) = 1;
y
end
Any more elegent way?

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回答（1 个）

John D'Errico
John D'Errico 2016-6-21
编辑：John D'Errico 2016-6-21
Will one line suffice?
y = sparse((1:5000)',reshape(repmat([10,1:9]',1,500)',[5000,1]),1,5000,10);

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