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Can some solve this without for loops ?

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Amelos
Amelos 2016-6-21
评论： Amelos 2016-6-21
a =rand(2,2,3); b = [ 1 2 3]; c = [1 2 3 4 5]; for n = 1: size(a,1) for m = 1:size(a,2) for s = 1: length(b) for k = 1: length(c) L(n,m,s,k)= a(n,m,s) +b(s)*a(n,m,s)*exp(c(k)*b(s)); end end end end
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John D'Errico
John D'Errico 2016-6-21
编辑：John D'Errico 2016-6-21
Given that you got an answer the last time you asked this question, and you accepted that answer, then why repost it? It seems you are asking essentially the same question repeatedly.
Amelos
Amelos 2016-6-21
I want to understand the approach. It is not the same. I changed the dimension of the matrix "a" (2->3). I solved in this way but I dont get the same answer: tmp = bsxfun(@times,reshape(b,1,1,[]),reshape(c,1,1,1,[])); tmp = bsxfun(@times,reshape(a,1,[]),exp(tmp)); tmp = bsxfun(@times,reshape(b,1,1,[]),tmp); tmp = bsxfun(@plus,reshape(a,1,[]),tmp);
Cheers

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