Finding a row with a certain condition

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AA
AA 2016-6-22
回答： Star Strider 2016-6-22
Assume I have the following matrix.
733458 91 1.01510000000000 1.01680000000000 1.01490000000000 1.01520000000000 1.01585000000000
733458 112 1.01620000000000 1.01620000000000 1.01400000000000 1.01610000000000 1.01510000000000
733458 135 1.01440000000000 1.01540000000000 1.01430000000000 1.01480000000000 1.01485000000000
733458 154 1.01420000000000 1.01580000000000 1.01410000000000 1.01420000000000 1.01495000000000
733458 173 1.01550000000000 1.01570000000000 1.01490000000000 1.01560000000000 1.01530000000000
I want to find the row that contains in column one the value 733458 and that is the closest to 158 in column 2. How can I do that?

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-6-22
A=[733458 91 1.01510000000000 1.01680000000000 1.01490000000000 1.01520000000000 1.01585000000000
733458 112 1.01620000000000 1.01620000000000 1.01400000000000 1.01610000000000 1.01510000000000
733458 135 1.01440000000000 1.01540000000000 1.01430000000000 1.01480000000000 1.01485000000000
733458 154 1.01420000000000 1.01580000000000 1.01410000000000 1.01420000000000 1.01495000000000
733459 173 1.01550000000000 1.01570000000000 1.01490000000000 1.01560000000000 1.01530000000000]
ii=ismember(A(:,1),733458)
B=A(ii,:)
[~,jj]=min(abs(A(ii,2)-158))
out=B(jj,:)

更多回答（1 个）

Star Strider
Star Strider 2016-6-22
One approach:
x = 158;
idx = find((M(:,1) == 733458) & ((x-M(:,2)).^2) == min( (x-M(:,2)).^2));
idx =
4

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