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numbering of matrices generation

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Ghulam Murtaza
Ghulam Murtaza 2016-6-23
编辑： Walter Roberson 2016-6-23
hi if i have
for j=1:3;
B=[A(j,1); A(j,1)]
end;
then how i got the matrices B1 B2 B3 instead of only B .
  1 个评论
KSSV
KSSV 2016-6-23
How we would know how you got it without telling what is A and what you wanted?

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回答（1 个）

Stephen23
Stephen23 2016-6-23
编辑：Stephen23 2016-6-23
>> A = randi(9,3,1)
A =
6
5
9
>> B1 = A([1,1],1)
B1 =
6
6
>> B2 = A([2,2],1)
B2 =
5
5
>> B3 = A([3,3],1)
B3 =
9
9
But almost always creating numbered variables is a really bad idea. Just use indexing instead, because indexing is faster, more reliable, neater, and easier to read and understand than trying to create variable names dynamically. Read these to know why:
http://www.mathworks.com/matlabcentral/answers/225435-save-variable-as-string-from-user-input
http://www.mathworks.com/matlabcentral/answers/267329-list-values-of-variables-with-wildcard
http://www.mathworks.com/matlabcentral/answers/196952-how-to-create-new-variables-in-batches-with-strcat
Or even better is to learn how to use MATLAB properly and avoid the loop altogether and use indexing:
>> A([1,1],1)
ans =
6
6
>> A([2,2],1)
ans =
5
5
Or if you really want to split A up into smaller matrices:
>> B = num2cell(A(:,[1,1]).',1);
>> B{1}
ans =
6
6
>> B{2}
ans =
5
5

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