How to compare multiple strings and assign values to the comparison?

5 次查看（过去 30 天）
German Preciat Gonzalez
评论： José-Luis 2016-6-28
I have data from 6 different sources in a form of strings. I want to compare which strings are the same.
So if I have:
d1='111'
d2='223'
d3='111'
d4='125'
d5='111'
d6='125'
d1,d3,d5 are the same, d4 and d6 are the same too and d2 is different to all, so I will like to receive a vector where similar strings have the same number, like this:
[1 2 1 4 1 4]
if all the strings are different I will like to receive something like this:
[1 2 3 4 5 6]
or all the same
[1 1 1 1 1 1]
so far I've use a very ugly program with a lot of IF and ISEQUAL, any suggestions I will really appreciate it!

请先登录，再回答此问题。

采纳的回答

José-Luis
José-Luis 2016-6-28
编辑：José-Luis 2016-6-28
Copying beginning from Siva because I'm lazy:
K = [{'111'} ; {'223'} ; {'111'} ; {'125'} ;{'111'} ; {'125'}] ;
Solving your problem more efficiently:
[val,ia,ib] = unique(K,'stable') ; % get unique values
your_answer = ia(ib);
  3 个评论
显示 1更早的评论
Guillaume
Guillaume 2016-6-28
I find that method of creating a cell array very odd!
K = {'111'; '223'; '111'; '125'; '111'; '125'};
is less to type and a lot simpler.

请先登录，再进行评论。

更多回答（3 个）

Guillaume
Guillaume 2016-6-28
Dr. Siva Srinivas Kolukula has the right idea: use unique. His answer is unnecessarily complicated though.
First though, do not use numbered variables. If they're numbered it means that they've got some sort of relationship. That relationship is much better expressed by putting the content of these variables together into the same container: matrix, cell array, map, table, etc. In your case, a cell array seems best.
Anyway, the third return value of unique is what you're after:
d = {'111', '223', '111', '125', '111', '125'}
[~, ~, uid] = unique(d, 'stable') %'stable' is optional. If not present unique ids are assigned alphabetically
  3 个评论
显示 1更早的评论
Guillaume
Guillaume 2016-6-28
Well, the question was "I will like to receive a vector where similar strings have the same number", which the above does.
José-Luis
José-Luis 2016-6-28
Indeed, but that's not what the example result showed. Anyway, interpreting questions is an art sometimes...

请先登录，再进行评论。

KSSV
KSSV 2016-6-28
编辑：KSSV 2016-6-28
clc; clear all ;
K = [{'111'} ; {'223'} ; {'111'} ; {'125'} ;{'111'} ; {'125'}] ;
[val,idx] = unique(K,'stable') ; % get unique values
iwant = zeros(size(K)) ; % initialize what you want
count = 0 ;
% loop for each equal string
for i = 1:length(idx)
count = count+1 ;
Index = strfind(K,val{i}) ;
Index = find(not(cellfun('isempty', Index))) ;
iwant(Index) = count ;
end
KSSV
KSSV 2016-6-28
Jose-Luis idea is good....but only one step is needed.
[val,ia,your_answer] = unique(K,'stable') ; % get unique values
  1 个评论
José-Luis
José-Luis 2016-6-28
No, what the op wanted, if I understood correctly, is the index to the first occurrence. Therefore that wouldn't work.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by