how to convert 2d to id

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studentambitious
studentambitious 2016-7-6
i want to convert a 5x3 matrix say A into 1d but before reshaping it i need to omit certain values from every row of A.number of values i need to omit is given in another matrix say C. for eg
A=[5 4 3 8 9 6; 2 1 3 2 5 ;4 3 5 7 6]
C=[1; 3; 4]
what i need is to convert matrix A into an array such that from first row of A last one value is to be emitted from second row last 3 values are to be removed and similarly from third row last 4 values need to be omitted. number of values to be omitted is given in row matrix C
please help
  2 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2016-7-6
You omitted to show us the expected result
Stephen23
Stephen23 2016-7-6
@studentambitious: your matrix A generates this error:
>> A=[5 4 3 8 9 6; 2 1 3 2 5 ;4 3 5 7 6]
Error using vertcat
Dimensions of matrices being concatenated are not consistent.

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回答(3 个)

KSSV
KSSV 2016-7-6
A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6] ;
B = [1 3 4] ;
iwant = fliplr(A) ;
for i = 1:length(B)
id = B(i) ;
iwant(i,1:id) = NaN ;
end
iwant = fliplr(iwant) ;
idx = ~isnan(iwant) ;
iwant = iwant(idx) ;

Azzi Abdelmalek
Azzi Abdelmalek 2016-7-6
编辑:Azzi Abdelmalek 2016-7-6
A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6]
C=[1; 3; 4]
n=size(A,2);
m=numel(C);
out=A(:);
idx=arrayfun(@(x) sub2ind(size(A),x*ones(1,C(x)),n:-1:n-C(x)+1),(1:m),'un',0)
idx=cell2mat(idx)
out(idx)=[]
%Or
A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6];
C=[1; 3; 4];
[n,m]=size(A);
B=zeros(1,n*m-sum(C));
idx=1;
for k=1:n
kk=1:m-C(k);
p=numel(kk);
B(1,idx:idx+p-1)=A(k,kk);
idx=idx+p;
end
B

José-Luis
José-Luis 2016-7-6
编辑:José-Luis 2016-7-6
Probably faster:
A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6];
C=[1; 3; 4];
numCol = size(A,2);
A(bsxfun(@gt,numCol - C,1:numCol)) = NaN
Please note that you did not specify how you wanted your results stored. Here, I replace the unnecessary data with NaN.

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