Fill in sequential numbers between two numbers

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Tyler Smith
Tyler Smith 2016-7-7
评论： the cyclist 2016-7-7
I have two matrices, A = (1,2,3,4,5) and B = (6,8,14,12,11). I need to generate an array in which all the numbers between A(row,1) and B(row,1), A(row,2) and B(row,2), etc. are filled in. It should look like this: outputarray = (1,2,3,4,5,6,2,3,4,5,6,7,8,3,4,5,6,7,8,9,10,11,12,13,14...). So the numbers between 1 and 6 (the first cells of A and B) would get filled in and so on down the line.

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采纳的回答

the cyclist
the cyclist 2016-7-7
Here's one way:
A = [1,2,3,4,5];
B = [6,8,14,12,11];
N = numel(A);
C = cell(1,N);
for ni = 1:N
C{ni} = A(ni):B(ni);
end
output = [C{:}]
  2 个评论
the cyclist
the cyclist 2016-7-7
You could also substitute this line in place of the for loop:
C = cellfun(@(x,y)x:y,num2cell(A),num2cell(B),'UniformOutput',false)

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更多回答（1 个）

James Tursa
James Tursa 2016-7-7
C = cellfun(@colon,mat2cell(A,1,ones(1,numel(A))),mat2cell(B,1,ones(1,numel(B))),'uni',false);
result = [C{:}];

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