split array
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if A = [1234567891234567];===> size(A) = 1*1
in one cell
I want split it as each (8digit) in one cell as:
A = [12345678;91234567];=====> size(A)= 2*1
回答（3 个）
Krishnendu Mukherjee
2012-2-18
0 个投票
for i=1:(size(A(1,:))/2) B(1,:)=A(1,i); end for i=(size(A(1,:))/2):size(A(1,:)) B(2,:)=A(1,i); end try this.it may work
3 个评论
Aseel H
2012-2-18
Krishnendu Mukherjee
2012-2-19
for i=1:(size(A(1,:))/2) B(1,i)=A(1,i); end for i=(size(A(1,:))/2):size(A(1,:)) B(2,i)=A(1,i); end try this.it may work
1 comment
Krishnendu Mukherjee
2012-2-19
i was in hurry yesterday.thats why little mistake
Andrei Bobrov
2012-2-18
A = 1234567891234567
B = reshape(num2str(A)-'0',[],2).'
Anew = B*10.^(size(B,2)-1:-1:0).'
Walter Roberson
2012-2-18
0 个投票
Your A is 16 digits long. You might not be able to store it accurately as a floating point number.
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