Puzzler: Count unique nonzero periods in a timeseries without a for loop

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Will Kinsman
Will Kinsman 2016-7-19
评论： Will Kinsman 2016-7-19
given: a signal as a time series
return: discrete number of times is is holds a nonzero position
For example:
given: [0,1,0.5,0.7,0,1]
return: 2
given: [0,1,0,0,0,.3,1,0,0,1]
return: 3
given: [0,1]
return: 1
is there a way to do this task in a vector manner as opposed to a for loop that counts nonzero periods as it encounters them and flicks a counter.

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2016-7-19
编辑：Azzi Abdelmalek 2016-7-19
a=[0,1,0,0,0,.3,1,0,0,1]
out=numel(strfind([0 logical(a)],[0 1]))

更多回答（1 个）

Image Analyst
Image Analyst 2016-7-19
Yes
[~, numRegions] = bwlabel(yourVector ~= 0);

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