How to solve "Index exceeds matrix dimensions" error?
显示 更早的评论
My question might be simple for most of you. Basically, I would like to delete a row of a matrix where a value of an element in column 6 is zero. In doing so, I run the following command.
load filename.txt;
for i = 1:length(filename)
if filename(i,6) = 0;
filename(i,:) = [];
end
end
However, the error message comes up saying that "Index exceeds matrix dimensions.". I don't understand why it exceeds the dimension because I have already specified that i = 1 to the length of the matrix. Any help on this would be appreciated. Thank you.
采纳的回答
Walter Roberson
2012-2-20
After you do the first deletion, the array is no longer as long as it used to be. The "for" limits are determined when the "for" is first encountered and are not adjusted at run-time.
(complete) Adjusted code:
load filename.txt
filename(filename(:,6) == 0, :) = [];
更多回答（2 个）
Oleg Komarov
2012-2-20
1 个投票
Because you're shrinking filename if the condition is verified.
Once you delete a row, the length of filename is one unit smaller but the loop is still setup from 1 to initial dimension of filename.
类别
在 帮助中心 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
